Khan Academy
Khan Academy: Geometry: 30 60 90 Triangles Ii
In this video tutorial, the instructor demostrates how to apply the special relationship between the legs and hypotenuse of a 30-60-90 triangle. Solves two different example problems using the relationship. Practice problems available....
Khan Academy
Khan Academy: Geometry: Rhombus Diagonals
Demonstrates how to prove that the diagonals of a rhombus are perpendicular bisectors of each other based on knowledge of triangle congruency postulates and properties of altitudes. [4:38]
Khan Academy
Khan Academy: Geometry: Challenging Perimeter Problem
Demonstrates how to solve a problem from the 2000 American Invitational Mathematics Examination which involves finding the perimeter of a rectangle covered by nine overlapping squares. [9:56]
Khan Academy
Khan Academy: Geometry: Incenter and Incircles of a Triangle
Explains that the intersection of the three angle bisectors of a triangle form the incenter of the triangle. [7:58]
Khan Academy
Khan Academy: Geometry: Proof Rhombus Area Half Product of Diagonal Length
Demostrates how to prove that one way to find the area of a rhombus is by taking half the product of the diagonals. [5:07]
Khan Academy
Khan Academy: Geometry: Quadrilateral Properties
This video tutorial [5:07] demonstrates how to use the basic properties of parallelograms, rectangles, squares, rhombi, and trapezoids to determine what are the possible ways to name a given geometric shape.
Khan Academy
Khan Academy: Geometry: Area of Koch Snowflake (Part 1) Advanced
Demonstrates how to find the area of a Koch snowflake by summing an infinite geometric series based on the area of an equilateral triangle. [12:30]
Khan Academy
Khan Academy: Geometry: Challenging Similarity Problem
Explains how to determine unknown side lengths in a complex diagram that involves similar triangles. [9:53]
Khan Academy
Khan Academy: Geometry: Corresponding Angle Equivalence Implies Parallel Lines
Proof by contradiction that if two lines cut by a transversal create congruent corresponding angles then the lines are parallel. [5:18]
Khan Academy
Khan Academy: Geometry: Koch Snowflake Fractal
Explanation of the Koch Snowflake and why it has an infinite perimeter but a finite area. [9:11]
Khan Academy
Khan Academy: Geometry: Equilateral Triangle Sides and Angles Congruent
In this video tutorial [6:29], the instructor models a proof so show that if the sides of an equilateral triangle are congruent, then all the angles are congruent and vice versa. The instructor uses the knowledge of congruent legs and...
Khan Academy
Khan Academy: Geometry: Finding Area Using Similarity and Congruence
Explains how to determine the area of a pentagonal shaded region in a triangle. The triangle that is broken into multiple similar and congruent triangles. [10:07]
Khan Academy
Khan Academy: Geometry: Two Column Proof Showing Segments Are Perpendicular
In this video tutorial [11:06], the instructor shows how to construct a two-column proof using triangle congruence postulates to prove that two line segments are perpendicular.
Khan Academy
Khan Academy: Geometry: Proof Rhombus Diagonals Are Perpendicular Bisectors
Demonstrates how to prove that the diagonals of a rhombus are perpendicular bisectors of each other based on knowledge of properties of parallelogram diagonals, triangle congruency, and supplementary angles. [4:04]
Khan Academy
Khan Academy: Geometry: Angle Game (Part 2)
Solving for unknown angle measures using knowledge of different angle relationships and the triangle sum theorem. Continuation of Angle Game video. [9:49]
Khan Academy
Khan Academy: Geometry: The Angle Game
Solving for unknown angle measures using knowledge of different angle relationships and the triangle sum theorem. [9:01]
Khan Academy
Khan Academy: Geometry: 45 45 90 Triangle Side Ratios
In this video tutorial [5:42], the instructor explains the ratio of the lengths of the sides in a 45-45-90 triangle using the Pythagorean theorem. Beginning of video concludes a discussion from a previous video on the ratio of the...
Khan Academy
Khan Academy: Geometry: Common Orthocenter and Centroid
Proves that if the orthocenter and centroid are the same point in a triangle then the triangle is a right triangle. [6:25]
Khan Academy
Khan Academy: Geometry: Intro to 30 60 90 Triangles
Solves an example problem in which the length of the hypotenuse is known and the length of a side must be determined. Explains the special relationship of the lengths of the sides of a 30-60-90 triangle using the Pythagorean theorem....
Khan Academy
Khan Academy: Geometry: Similar Example Problems
Explains how to identify and use similar triangles in order to determine unknown side lengths in two given diagrams. Each diagram also applies knowledge of angles formed when parallel lines are cut by a transversal. [7:37]
Khan Academy
Khan Academy: Geometry: Exploring Medial Triangles
This video tutorial [11:32] explains what a medial triangle is and proves that the medial triangle divides the original triangle into four congruent triangles. Proof uses triangle similarity and triangle congruence postulates.
Khan Academy
Khan Academy: Geometry: 30 60 90 Triangle Side Ratios Proof
In this video tutorial [6:59], the instructor provides a proof for the relationship among the legs and hypotenuse of 30-60-90 triangles by breaking an equilateral triangle into two congruent triangles and using the Pythagorean threorem.
Khan Academy
Khan Academy: Geometry: Similarity Example Where Same Side Plays Different Roles
Explains how to determine unknown side lengths in a diagram that involves similar triangles where the two triangles share a side and the shared side corresponds to two different sides in each triangle. [6:05]
Khan Academy
Khan Academy: Geometry:sss to Show a Radius Is Perpendicular to Chord It Bisects
Explains how to prove that a radius is perpendicular to a chord that it bisects by using the side-side-side triangle congruence postulate. [8:19]
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