Instructional Video9:44
Curated OER

Introduction to Rate-of-Change Problems

11th - Higher Ed
Sal solves an example for finding the rate of change of the height of water in a cone at a specific point when it is being filled at a given rate. In this video, Sal reviews the volume of a cone and the chain rule and then, uses these to...
Instructional Video9:37
Curated OER

Maxima Minima Slope Intuition

11th - Higher Ed
Before solving any problems, Sal gives an overview of what happens to the slope, first derivative, and second derivative at local maxima and minima to give the viewer a more intuitive feel for these types of problems.
Instructional Video9:48
Curated OER

Optimization Example 4

11th - Higher Ed
Sal does another optimization example, this time, minimizing the total cost of an open rectangular box. In this problem, the volume can be defined in terms of a single variable and given a cost model, he builds a cost equation. He finds...
Instructional Video9:44
Curated OER

Graphing with Calculus

11th - Higher Ed
In a problem where you are not given the original function, but rather only three known points on the graph and a few additional pieces of information about when the first and second derivatives are positive or negative, Sal shows how...
Instructional Video17:30
Curated OER

Optimization with Calculus 3

11th - Higher Ed
Using what one learned about finding the minimum and maximum of functions, the optimization problem to find two numbers whose product is -16 and whose sum of squares is a minimum is solved. Sal starts by writing the equations and...
Instructional Video7:03
Khan Academy

Proof: d/dx(x^n)

11th - Higher Ed
Using the binomial theorem and definition of a limit, Sal shows a proof that the derivative of xn equals nxn-1.
Instructional Video5:07
Khan Academy

Proof: d/dx(sqrt(x)) Taking Derivatives Differential Calculus

11th - Higher Ed
Using the definition of a limit, Sal proves that the derivative of x or x1/2 equals _ x-1/2.
Instructional Video9:52
Khan Academy

Proof: d/dx(ln x)=1/x

11th - Higher Ed
Using the definition of a limit, various properties of logarithms, and a definition of e, Sal shows the proof of the derivative of ln x = 1/x. Note: The video titled "Proof of Derivatives of Ln(x) and e^x,Ó has a more straightforward...
Instructional Video4:40
Khan Academy

Proof: d/dx(e^x) = e6x

11th - Higher Ed
Using the derivative of ln x, the chain rule, and the definition of a limit, Sal shows proof that the derivative of ex = ex. Note: The video titled "Proof of Derivatives of Ln(x) and e^x,Ó clearly explains this proof.
Instructional Video8:07
Khan Academy

Equation of a Tangent Line, Taking Derivatives, Differential Calculus

11th - Higher Ed
Using a specific example, Sal shows how to find the equation of a tangent line to a given function at a specific point. Specifically, he solves the problem of finding the tangent line to the function f(x) = xex at x = 1. This problem...
Instructional Video9:50
Khan Academy

Power Rule Introduction (Old) Taking derivatives, Differential Calculus

11th - Higher Ed
This video covers the differential notation dy/dx and generalizes the rule for finding the derivative of any polynomial. It also extends the notion of the derivatives covered in the Khan Academy videos, "Calculus Derivatives 2Ó and...
Instructional Video9:32
Khan Academy

Calculus: Derivatives 2

11th - Higher Ed
Sal continues where he left off with the last video, "Derivatives 1, Ó by looking at the equation y = x^2 and examining the slope of the second line at a specific point, and again defining the limit as x approaches zero to get the slope...
Instructional Video11:05
Khan Academy

The derivative of f(x)=x^2 for any x Taking derivatives, Differential Calculus

11th - Higher Ed
By defining the formal definition of a derivative, f(x), Sal can find the general form of the derivate function for the example f(x) = x2. He continues to stress the importance of an intuitive understanding of derivative functions.
Instructional Video8:35
Khan Academy

Calculus: Derivatives 2 (New HD Version)

11th - Higher Ed
Sal continues where he left off with the last video, "Derivatives 1, Ó by looking at the equation y = x2 and examining the slope of the second line at a specific point. He continues defining the limit as x approaches zero to get the...
Instructional Video9:26
Khan Academy

Calculus: Derivatives 1

11th - Higher Ed
Sal defines the term derivative by taking the listener on a well-organized tour of the slope. First, he reviews the concept of the slope of a line from algebra, then extends this idea to look at the slope of the curve by first examining...
Instructional Video15:43
Khan Academy

Calculus: Derivatives 1 (New HD Version)

11th - Higher Ed
Sal defines the term derivative by taking the listener on a well-organized tour of the slope. First, he reviews the concept of the slope of a line from algebra, then extends this idea to look at the slope of the curve by first examining...
Instructional Video9:02
Khan Academy

Calculus: Derivative of x^(x^x)

11th - Higher Ed
Sal starts by showing how to find dy/dx of y = x2 and then moves on to show the solution to the more complicated implicit differentiation problem of finding the derivative of y in terms of x of y = x ^ x ^ x.
Instructional Video16:48
Khan Academy

Mean Value Theorem, Derivative Applications, Differential Calculus

11th - Higher Ed
Sal spends most of this video explaining the Mean Value Theorem in a very intuitive way. He follows this with a concrete example of finding the value of a function on a closed interval where the slope is the same as the average slope of...
Instructional Video8:49
Khan Academy

Product Rule, Taking Derivatives, Differential Calculus

11th - Higher Ed
Sal defines the product rule and then shows two examples of its use. He then shows an example of finding the derivative using the chain and product rules together.