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Proof: lim (sin x)/x Instructional VideoProof: lim (sin x)/x Instructional Video
Publisher
Khan Academy
Resource Details
Curator Rating
Educator Rating
Not yet Rated
Grade
11th - Higher Ed
Subjects
Math
2 more...
Resource Type
Instructional Videos
Media Length
18:05
Audiences
For Teacher Use
1 more...
Duration
30 mins
Instructional Strategies
Flipped Classroom
1 more...
Accessibility
Closed Captions
1 more...
Year
2008
Usage Permissions
Creative Commons
BY-NC-SA: 3.0
cc
Instructional Video

Proof: lim (sin x)/x

Curated and Reviewed by Lesson Planet

By looking at the expression (sin x)/x that is not defined at the limit value of 0, Sal uses the squeeze theorem to show that the function can be bound between two other functions that are defined at the limit value, so the limit can indeed be found.

3 Views 2 Downloads

Concepts

the squeeze theorem, differential calculus

Additional Tags

squeeze theorem, squeeze law, differential calculus, math

Classroom Considerations

  • This video is hosted on YouTube

View 13,803 other resources for 11th - Higher Ed Grade Math

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