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Challenge algebra learners to use the difference of cubes to solve this problem. Once your charges have taken out the factor (a - b), combined the like terms and set them equal to zero, the problem becomes a factorable quadratic equation. Some pupils may use the quadratic formula to solve. Both solutions are illustrated in the resource.
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Pros
The problem makes a great assessment question because it tests students' knowledge of the identity, difference of cubes and solving a quadratic equation.
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