Khan Academy
Khan Academy: Algebra: Officer on Horseback
This video demonstrates how to set up and solve a system of equations in order to answer a question posed in a word problem. The solution utilizes the equation d=rt. [8:54]
Khan Academy
Khan Academy: Algebra: Two Passing Bicycles Word Problem
This video demonstrates how to apply systems of equations to a word problem about two people passing each other on bicycles. The problem also involves constant speeds and distances. [5:39]
Khan Academy
Khan Academy: Algebra: Passed Bike Word Problem
This video demonstrates how to set up and solve a system of equations in order to answer a word problem based on rates and elapsed time. [5:54]
Khan Academy
Khan Academy: Algebra: Passing Trains
This video demonstrates how to solve a systems of equations word problem related to the rates of passing trains. The problem involves finding a rate in meters/second and setting up and solving a system of equations. [9:07]
Khan Academy
Khan Academy: Algebra: Problem Solving Word Problems 2
A video that demonstrates how to set up and solve systems of equations in order to answer word problems. [12:20]
Khan Academy
Khan Academy: Trigonometry: Navigation Word Problem
Video showing how to solve a navigation word problem with speeds and distances using trigonometry. [8:00]
Khan Academy
Khan Academy: Algebra: Algebra Ii: Functions, Combinatorics
Video solving problems 60 to 65 of the California Standards Test for Algebra II. Concepts covered include negative exponents, square root equations and inequalities, permutations, and probability. [11:25]
Khan Academy
Khan Academy: Algebra: Mixture Problems 3
This video demonstrates how to solve a mixture problem by using a table and solving an equation. [4:07]
Khan Academy
Khan Academy: Algebra: Mixture Problems 2
This video demonstrates how to solve a mixture problem by setting up and solving a system of equations. [6:43]
Khan Academy
Khan Academy: Algebra: Three Equation Application Problem
This video demonstrates how to solve a problem in a geometry context by setting up and solving a systems of equations in three variables. [8:15]
Khan Academy
Khan Academy: Algebra: Substitution Method 3
This video demonstrates how to solve a word problem by setting up and solving a system of equations. Uses the substitution method. [5:58]
Khan Academy
Khan Academy: Calculus: 2011 Calculus Bc Free Response #1 (B & C)
Video shows how to find the slope of the tangent line to a particles path using the derivatives of the parametric equations representing the particle. Also shows how to integrate the derivatives of the parametric equations along with...
Khan Academy
Khan Academy: Algebra 2: Applying Rational Equations 3
A step-by-step breakdown on how to solve a rational equation in a real-world application problem. [7:59]
Khan Academy
Khan Academy: Pre Calculus: Compound Interest and E (Part 2)
Continuing from a previous video, this segment illustrates that as interest is compounded at increasingly more intervals, the debt owed approaches the number e (if $1 is borrowed at a rate of 100%). The instructor provides the ground...
Khan Academy
Khan Academy: Algebra 2: Applying Rational Equations 2
A step-by-step breakdown on how to solve a rational equation in a real-world application problem. [6:00]
Khan Academy
Khan Academy: Algebra: Richter Scale
Discusses the Richter scale as a logarithmic scale and explains how to interpret the magnitudes of four different earthquakes. [11:19]
Khan Academy
Khan Academy: Algebra: Patterns and Equations
This video has several problems that deal with writing equations. The first problem illustrates how to write an equation to represent the relationship between variables in a table. The rest of the sample problems demonstrate how to take...
Khan Academy
Khan Academy: Pre Calculus: Compound Interest and E (Part 3)
Another segment in the series on compound interest and the number e from the Khan Academy. This video begins to derive the formula for interest compounded continuously (A=Pe^rt). Limits are employed to show that the limit of the interest...
Khan Academy
Khan Academy: Pre Calculus: Compound Interest and E (Part 4)
In this culminating segment in the video series about compound interest and e, the formula for interest being compounded continuously is fully derived. Examples are then given on how to use the formula for different types of interest...
Khan Academy
Khan Academy: Algebra: Graphical Systems Application Problem
This video demonstrates how to solve a word problem that requires setting up and solving a system of equations. The problem requires that the system of equations be solved graphically. [5:19]
Math TV
Math tv.com: Right Triangle Trigonometry: Applications
The examples examine application problems that use right triangles. The learning resource consists of a video tutorial and a worksheet with practice problems. In the left hand menu, click Trigonometry, Right Triangle Trigonometry,...
Sophia Learning
Sophia: Solving Absolute Value Inequalities: Lesson 11
Throughout this lesson, you'll learn how to calculate the two possible solutions from an algebraic inequality that includes the absolute value of an expression. It is 11 of 11 in the series titled "Solving Absolute Value Inequalities."
Sophia Learning
Sophia: Solving Absolute Value Inequalities: Lesson 4
Throughout this lesson, you'll learn how to calculate the two possible solutions from an algebraic inequality that includes the absolute value of an expression. It is 4 of 11 in the series titled "Solving Absolute Value Inequalities."
Khan Academy
Khan Academy: Systems of Equations Word Problems: Systems and Rate Problems 2
This video demonstrates how to set up and solve a system of equations in order to solve a word problem concerning rates.