Instructional Video2:12
Brian McLogan

Learn to solve a proportion by determining & multiplying by LCD ex 14,(2x–11)=5(x–3)/11

12th - Higher Ed
👉 Learn how to solve proportions. Two ratios are said to be proportional when the two ratios are equal. Thus, proportion problems are problems involving the equality of two ratios. When given a proportion problem with an unknown, we...
Instructional Video2:39
Brian McLogan

Learn to solve a proportion by mulitplying both sides by the LCD (4x+5)/5 = (2x+7)/7

12th - Higher Ed
👉 Learn how to solve proportions. Two ratios are said to be proportional when the two ratios are equal. Thus, proportion problems are problems involving the equality of two ratios. When given a proportion problem with an unknown, we...
Instructional Video2:59
Brian McLogan

Solve a proportion by multiplying by the LCD ex 13, (2n - 9)/7 = (3 - n)/4

12th - Higher Ed
👉 Learn how to solve proportions. Two ratios are said to be proportional when the two ratios are equal. Thus, proportion problems are problems involving the equality of two ratios. When given a proportion problem with an unknown, we...
Instructional Video3:24
Curated Video

GCSE Secondary Maths Age 13-17 - Ratio, Proportion & Rates of Change: Inverse Proportionality - Explained

9th - 12th
SchoolOnline's Secondary Maths videos are brilliant, bite-size tutorial videos delivered by examiners. Ideal for ages 13-17, they cover every key topic and sub topic covered in GCSE Maths in clear and easy to follow steps. This video...
Instructional Video5:46
Brian McLogan

Dividing two rational expression by factoring to simplify

12th - Higher Ed
Learn how to divide rational expressions. A rational expression is an expression in the form of a fraction, usually having variable(s) in the denominator. Recall that to divide by a fraction, we multiply by the reciprocal of the...
Instructional Video2:10
Brian McLogan

Learn how to solve a proportion by applying the cross product ex 15, 15/(x+7) = 45/(x+21)

12th - Higher Ed
👉 Learn how to solve proportions. Two ratios are said to be proportional when the two ratios are equal. Thus, proportion problems are problems involving the equality of two ratios. When given a proportion problem with an unknown, we...
Instructional Video6:05
Brian McLogan

Apply the law of sines when you are given AAS

12th - Higher Ed
👉 Learn how to solve for the length of the sides and the measures of the angles of a triangle using the law of sines. The law of sines is used in determining the length of the opposite side to a known angle measure or the measure of the...
Instructional Video3:24
Brian McLogan

Introduction to rationalizing the denominator to simplify a radical expression

12th - Higher Ed
👉 Learn how to divide rational expressions with a radical in the denominator. To divide rational expressions with a radical in the denominator, we rationalize the denominator by multiplying both the numerator and denominator by the...
Instructional Video5:17
Curated Video

Compare Real World Unit Rate

9th - 12th
In this short video we will answer a standardized math test open response question where we are asked to find and compare unit rates in the real world. We will compare the price per ounce for two different size boxes of crackers. We will...
Instructional Video11:29
Curated Video

Proportions

9th - 12th
In this video lesson we will learn how to write and solve a proportion. We will use a proportion to determine if two ratios are equal. We will learn that if two ratios form a proportion there is a proportional relationship. We will solve...
Instructional Video1:01
Brian McLogan

Using the triangle midsegment theorem to find the missing midsegment

12th - Higher Ed
👉 Learn how to solve for the unknown in a triangle divided internally such that the division is parallel to one of the sides of the triangle. The triangle proportionality theorem states that if a line is parallel to one side of a...
Instructional Video7:21
Brian McLogan

Using the law of sines to solve a triangle with SSA - One Triangle

12th - Higher Ed
👉 Learn how to determine if a given SSA triangle has 1, 2 or no possible triangles. Given two adjacent side lengths and an angle opposite one of them (SSA or ASS), then there are 3 possible cases: there can be 1 solution, 2 solutions,...
Instructional Video1:00
Brian McLogan

Tutorial - Determine if an equation is an example of direct variation ex 4, y= 1/5x

12th - Higher Ed
In this video I will show you how to use direct variation to help determine the missing variable, as well as how to determine if an equation is an example of direct variation or not. For an equation to be an example of direct variation...
Instructional Video12:18
Curated Video

How You Can Determine Similarity

9th - 12th
In this video lesson, we will learn the definition of similar figures. Similar figures are figures that are the same shape but different sizes. Similar figures have corresponding sides that are proportional and corresponding angles that...
Instructional Video6:21
Brian McLogan

Using a set of points to determine if two triangles are similar to each other

12th - Higher Ed
👉 Learn how to determine whether two triangles are similar given the coordinate points of the vertices of the triangle. Two triangles are said to be equal when the corresponding angles of the triangles are congruent (equal) or when the...
Instructional Video3:53
Brian McLogan

Showing two triangles are similar when they overlay each other using SAS

12th - Higher Ed
👉 Learn how to solve for the unknown in a triangle divided internally such that the division is parallel to one of the sides of the triangle. The triangle proportionality theorem states that if a line is parallel to one side of a...
Instructional Video5:20
Brian McLogan

How to find the missing parts of a triangle using law of sines

12th - Higher Ed
👉 Learn how to solve for the length of the sides and the measures of the angles of a triangle using the law of sines. The law of sines is used in determining the length of the opposite side to a known angle measure or the measure of the...
Instructional Video5:32
Brian McLogan

Find the missing measure of a triangle given AAS Law of Sines

12th - Higher Ed
👉 Learn how to solve for the length of the sides and the measures of the angles of a triangle using the law of sines. The law of sines is used in determining the length of the opposite side to a known angle measure or the measure of the...
Instructional Video1:49
Brian McLogan

How to determine the altitude by using the geometric mean

12th - Higher Ed
Learn about the geometric mean of numbers. The geometric mean of n numbers is the nth root of the product of the numbers. To find the geometric mean of n numbers, we first multiply the numbers and then take the nth root of the product.
Instructional Video1:42
Brian McLogan

How to determine the ratio of a reduction dilation

12th - Higher Ed
👉 Learn about dilations. Dilation is the transformation of a shape by a scale factor to produce an image that is similar to the original shape but is different in size from the original shape. A dilation that creates a larger image is...
Instructional Video1:48
Brian McLogan

How to apply the triangle proportionality theorem to determine the missing side

12th - Higher Ed
👉 Learn how to solve for the unknown in a triangle divided internally such that the division is parallel to one of the sides of the triangle. The triangle proportionality theorem states that if a line is parallel to one side of a...
Instructional Video6:54
Brian McLogan

How to use law of sines when you have one solution

12th - Higher Ed
👉 Learn how to determine if a given SSA triangle has 1, 2 or no possible triangles. Given two adjacent side lengths and an angle opposite one of them (SSA or ASS), then there are 3 possible cases: there can be 1 solution, 2 solutions,...
Instructional Video4:48
Brian McLogan

Solving SSA with law of sines and no solution

12th - Higher Ed
👉 Learn how to determine if a given SSA triangle has 1, 2 or no possible triangles. Given two adjacent side lengths and an angle opposite one of them (SSA or ASS), then there are 3 possible cases: there can be 1 solution, 2 solutions and...
Instructional Video1:41
Brian McLogan

How to solve a proportion with an expression over another ex 18, (c + 1)/(c - 2) = 4/7

12th - Higher Ed
👉 Learn how to solve proportions. Two ratios are said to be proportional when the two ratios are equal. Thus, proportion problems are problems involving the equality of two ratios. When given a proportion problem with an unknown, we...